Please help! I will mark the brainliest! How do you graph the equation...
y=6x+600
y=8x
y=1300+3x
with a domain of 0 t 650 and a range of 0 d 1500

The first is in the form y=Mx+b where m is the slope and b is the y-intercept. Start at 600 on the y-axis and graph with a slope of six. The second is in the same form but the y-intercept is 0, so start at the origin and graph with a slope of 8. The last is in the form y=b+mx, so start at 1300 and graph with a slope of 3. Remember, slope is rise/run or (change in y)/(change in x). Since the domain and range start at 0 these graphs will only be in the first quadrant with an x limit of 650 and a y limit of 1500.

Answer: v= lwhstep by step explanation: length x width x heightl = 12kmw = 6kmh = 6km12 x 6 = 7272 x 6 = 432therefore your answer would be c) 432 km^3