RIGHT TRIANGLES & TRIGONOMETRY MATH
TOMMOROW DUE PLZZZ

sin d= 20/29

cos d= 21/29

tan d= 20/21

sin e= 21/29

cos e= 20/29

tan e= 21/20

7) x=47  (25tan(62))

8) x=25.1 (11/sin(26))

9) x=23.8 (32sin(48))

10) x=29.6 (29/cos(12))

11) x=21 degrees (invcos(14/15))

12) x=39.6 degrees (invtan(19/23))

13) x=58 degrees (invcos(9/17))

14) x=72.9 degrees (invsin43/45))

Step-by-step explanation:

good luck m8 it gets harder trust me

also srry if something is wrong im so exhausted thxbye

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

6 adults and 9 children went.

a + c = 15

12a + 9c = 153

12(6) + 9(9) = 153

72 + 81 = 153