Please help me. The coordinates for the vertices of quadrilateral ABCD are A(-3,2) B(-2,6) C(2,7) and D(1,3). Use this information to answer the questions below.
Slope of side AB:
A. 1/4
B. 4/1
C. -1/4
D. -4/1

Slope of side CD
A. 1/4
B. 4/1
C. -1/4
D. -4/1

Slope of side DA
A. 1/4
B. 4/1
C. -1/4
D. -4/1

Classify the quadrilateral
A. Square
B. Rectangule
C. Rhombus
D. Parallelogram
E. Trapezoid

the answer is ! ?

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.