Triangle A'B'C' with coordinates of A' (-6,2)

(A), (B) and (E).

Step-by-step explanation: Given that ΔA’B’C’ with coordinates of A(-6,2),B’(-4,2), and C’(-6,-2) is the image of ΔABC after a translation of (x-3,y+2). We are to find the possible coordinates for the original vertices of ΔABC.

For vertex A, we have

So, the coordinates of vertex A are (-3, 0).

For vertex B, we have

So, the coordinates of vertex B are (-1, 0).

For vertex C, we have

So, the coordinates of vertex C are (-3, -4).

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you