A new car is purchased for 20700 dollars. The value of the car depreciates at 11% per year. What will the value of the car be, to the nearest cent, after 11 years?

5744. 61 cents

Step-by-step explanation:

5744. 61 cents

Because:

Explanation:

after 1 year:

20700×89%=18423

after 2 years:

18423×89%=16396.47

after 3 years:

16396.47×89%=14592.8583

after 4 years:

14592.8583×89%=12987.64389

after 5 years:

12987.64389×89%=11559.00306

after 6 years:

11559.00306×89%=10287.51272

after 7 years:

10287.51272×89%=9155.886323

after 8 years:

9155.886323×89%=8148.738828

after 9 years:

8148.738828×89%=7252.377557

after 10 years:

7252.37757×89%=6454.616026

after 11 years:

6454.616026×89%=5744.608263

~5744.61 (nearest cent)

answer: the 4 kilogram bag

step-by-step explanation: this is because if you divide the number of kilograms into the total it will tell you how much each individual kilogram would be worth. 2 kilos is 7 and change 3 would be around 6 ish and the 4 kilo would be 4.6 and change and the 5 kilos would be like 4.88

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.