Can somebody please help meee out ?? I don’t understand this .

(-5,3)-3/2=(-1,-3)

Step-by-step explanation:

So the slope intercept form is 3/2 and the points are (-5,3) and (-1,-3)

y intercept form is y=mx+b.

I hope one of those helps

the equation for the function shown is y= -3/2x -9/2

Step-by-step explanation:

You can find the slope of the graph by counting how many spaces up or down over how many spaces left or right between two points. Start from the left of the graph and go towards the right of the graph when doing this. If you count the spaces between the two points on the graph, it is down six units (-6 on top) and 4 units right (4 on bottom) to get a slope of -6/4, which can be simplified by dividing both the top and bottom by two to get a slope of -3/2. Next you can use the point-slope form to find the equation of the graph in the form y=mx + b. Point slope form looks like this: y-y1=(the slope)(x-x1).

Plug in what you got for the slope and the coordinates for any point on the graph (the y coordinate replacing y1 and the x coordinate replacing x1). Here, I used the point (-1, -3), but you should get the same answer no matter what point you use, as long as it is a point on the graph:=> y-(-3)= -3/2(x-(-1))

=>y+3=-3/2(x+1)

distribute the -3/2 to both terms in the parentheses: y+3= -3/2x -3/2

subtract 3 from both sides to get y by itself (aka to convert to the form y=mx+b): y= -3/2x -9/2 (Here, -9/2 is your y-intercept, or where the graph crosses the y-axis).

i will u if u answer my question in math

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.