What is the equaton of the line through 4, 5 and 0, -3

(2,1) i believe (?)

(4,5) (0,-3)

you add the x’s so the 4 and the 0 which is 4 then you divide it by 2 since there are two x numbers. for the y you would do the same 5+-3 ( plus and a minus makes a minus, 5-3) which is 2 then divide it by 2 again. Finally you get (2,1)

Ithink the answer is c just trying to others