Four segments measure 16, 19, 43 and 50 centimeters. what is the probability that a triangle can be formed if three of these segments are chosen at random?

OK, a triangle first of all needs to have a certain condition satisfied. The length of one side of a triangle can not equal the length of 2 sides combined. So in a triangle a + b = c, a + b can not be less than c (a + b ≮ c). Therefore, there are only a few possibilities that will work here. Let's find them:

16, 19, 43; no

16, 19, 50; no

16, 43, 50; yes

19, 43, 50; yes 

Since only 2 out of 4 form triangles, there is a 50% chance you'll pick the right segments to form a triangle.

40 & 50 in the right corner are the complementary angles as when placed in a sum (added together) they make 90°

Ithink you're supposed to multiply 12.50 which is how much he makes per hour and then multiply it by each number then add whats left togrther and there's your answer