A projectile is launched from ground level with an initial velocity of V0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s= - 161? + vot. Find the time(s) that the projectile will (a) reach a height of 400 ft and (b) return to the ground when vo is 128 feet per second.
(a) Find the time(s) that the projectile will reach a height of 400 ft when Vo = 128 feet per second.

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step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.