Given: ABCD is a parallelogram. Prove: AB CD and BC DA
AnglesSegments Triangles StatementsReasons
ZBAC
ZBCA
ZDAC
ZDCA
B
Statements
Reasons
A
Assemble the proof by dragging tiles to
the Statements and Reasons columns.

Sorry, I am a little late.

step-by-step explanation:

10.50 + taxes which added up to 11.50

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source: