d) by the cross product property, ab^2 = bc multiplied by ad
step-by-step explanation:
we are given
in the given triangle abc
angle a is 90° and segment ad is perpendicular to segment bc
we can see that
triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)
so, triangles(abc) and abd are similar
since, they are similar
so, the ratio of their sides must be equal
we get
![\frac{ab}{bc} =\frac{ad}{ab}](/tex.php?f=\frac{ab}{bc} =\frac{ad}{ab})
now, we can cross multiply
and we get
![ab\timesab=ad\times bc](/tex.php?f=ab\timesab=ad\times bc)
![ab^2=ad\times bc](/tex.php?f=ab^2=ad\times bc)
so, this could be step to prove it
![Seth is using the figure shown below to prove pythagorean theorem using triangle similarity: in the](/tpl/images/02/04/LzDC4XcDVYxsMHOp.jpg)