If F is a field, R a nonzero ring, and f: F >> R a surjective homomorphism, prove that f is an isomorphism.

we will assume Ker f = {0} or Ker f = F

when Ker f = 0 ( nothing to prove )

but when Ker f = F

f ( x ) = 0 ,  ∀x ∈ F

as ⇒Im F = 0

but when F = R and R ≠ 0 , it proves that ker f = {0}

and this proves that f is an isomorphism

Step-by-step explanation:

F been a subjective homomorphism shows that f is one-one

Therefore to prove that f is an isomorphism

we will assume Ker f = {0} or Ker f = F

when Ker f = 0 ( nothing to prove )

but when Ker f = F

f ( x ) = 0 ,  ∀x ∈ F

as ⇒Im F = 0

but when F = R and R ≠ 0 , it proves that ker f = {0}

and this proves that f is an isomorphism

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

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