Line v passes through point [6.6] and is perpendicular to the graph of y= 3/4x - 11 line w is parallel to line v and passes through point [-6,10] what is the equation in slope intercept form of line w please help im in a exam

Given:

The equation of a line is

Line v passes through point (6,6) and it is perpendicular to the given line.

Line w passes through point (-6,10) and it is parallel to the line v.

To find:

The equation in slope intercept form of line w.

Solution:

Slope intercept form of a line is

        ...(i)

where, m is slope and b is y-intercept.

We have,

     ...(ii)

On comparing (i) and (ii), we get

So, slope of given line is .

Product of slopes of two perpendicular lines is -1.

Line w is perpendicular to the given line. So, the slope of line w is .

Slopes of parallel line are equal.

Line v is parallel to line w. So, slope of line v is also .

Slope of line v is and it passes thorugh (-6,10). So, the equation of line v is

where, m is slope.

Adding 10 on both sides, we get

Therefore the equation of line v is .

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.