? The area of a square can be shown using y = x2 - 4x + 4 and the perimeter of the same square can be shown using y = -2x + 4. Which
value(s) for x would make the area and perimeter equal?
x = 0 ANS
X = 2
А
B.
x=O ONLY
C.
x = 2 ONLY
D.
x=0, x= 2 AND X = 4

The values of x is 0 and 2.

Step-by-step explanation:

Given that the perimeter and area are the same so we can assume that x value remains the same in both equation. In order to find x, we can compare the equations and solve it :

A(y) = x² - 4x + 4

P(y) = -2x + 4

A(y) = P(y)

x² - 4x + 4 = -2x + 4

x² - 4x + 4 + 2x - 4 = 0

x² - 2x = 0

x(x - 2) = 0

x = 0

x - 2 = 0

x = 2

21/58.

hope to be marked brainliest

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol