Find a polynomial with a degree of 3, and the zeros 1,7, & -4 with no other zeros.

Step-by-step explanation:

zeroes are when you plug in that x value and get y=0

therefore if you set x = that number and solve for 0 you get a "function"

multiplying these together will yield the complete 3rd degree polynomial

x = 1

x-1=0

x=7

x-7=0

x=-4

x+4=0

If needed you could expand but I'm too lazy

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

d. all of the above

step-by-step explanation: