Cot^2(alpha)csc(alpha)+2cot(alpha)c sc(alpha)-3csc(alpha)

Step-by-step explanation:

cot²α csc α+2 cot α csc α-3 csc α

=csc α (cot²α+2cot α-3)

=csc α (cot² α+3cot α- cot α-3)

=csc α[cot α(cot α+3)-1(cot α+3)]

=csc α (cot α+3)(cot α-1)

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

i don't have the answer rn but go to math papa. it shows the steps and the answer. hope this : )

step-by-step explanation: