Please help The function shown is reflected across the y-axis to create a new function.

Which is true about the domain and range of each function?

A. Both the domain and range change.
B. Both the range and domain stay the same.
C. The domain stays the same, but the range changes.
D. The range stays the same, but the domain changes

D. The range stays the same, but the domain changes.

Step-by-step explanation: A function can be reflected over or across an axis. When the function is reflected in the y-axis, it means:

g(x) = f(-x)

i.e, the x-values are opposite to the original function.

In the image below, when we reflected the function across the y-axis, the new one will be drawn at the positive x-axis but still at the negative y-axis as shown in red at the second attachment.

Domain of a function is all the values x can assume. Range of a function is all the results the variable y assume.

According to the new graph, y-values didn't change, so Range stays the same. However, x-values changed their signal. Therefore, domain changes.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

i am unable to solve this problem

step-by-step explanation: