A phone company produces 40 defective phones out of every 5000 phones. Another cell phone company produces 30 defective phones out of every 6000 phones. What is the highest number of defective phones the phone companies have in common?

10

Step-by-step explanation:

We have that:

The first company

Company A:

Produces 40 defective out of every 5000

The second company

Company B produces:

30 defective out of every 6000

We are to ge the highest number of defective phones that both of these companies can produce in common:

So we get the Factors of the number of defectives produced by both :

Factors of 40 : 2, 4, 5, 8, 10, 20, 40

Factors of 30 : 2, 3, 5, 6, 10, 15, 30

From the above we can see that the highest number of defective phones that both companies can produce in common is 10.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

y=1/4x-4

step-by-step explanation: