Find a third degree polynomial function of the lowest degree that has the zeros below and whose leading coefficient is one. -1,0,6

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is .

Step-by-step explanation:

From Fundamental Theorem of Algebra, we remember that the degree of the polynomials determine the number of roots within. Since we know three roots, then the factorized form of the polynomial function with the lowest degree is:

(1)

Where , and are the roots of the polynomial.

If we know that , and , then the polynomial function in factorized form is:

(2)

And by Algebra we get the standard form of the function:

(3)

The polynomial function of the lowest degree that has zeroes at -1, 0 and 6 and with a leading coefficient of one is .

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3