Let v =LeftAngleBracket negative 10, 15 RightAngleBracket. What is the approximate direction angle of One-halfv? 34° 56° 124° 304°

The approximate angle of , where , is 56º.

Step-by-step explanation:

Let and , then the resulting vector is described below:

From Trigonometry, we find that direction angle of this vector is defined by the following inverse trigonometric expression:

(1)

Where:

- x-Component of , dimensionless.

- y-Component of , dimensionless.

If we know that and , then the direction angle of the vector is:

The approximate angle of , where , is 56º.

C. 124

Step-by-step explanation:

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

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