Let v =LeftAngleBracket negative 10, 15 RightAngleBracket. What is the approximate direction angle of One-halfv? 34° 56° 124° 304°

The approximate angle of , where , is 56º.

Step-by-step explanation:

Let and , then the resulting vector is described below:

From Trigonometry, we find that direction angle of this vector is defined by the following inverse trigonometric expression:

(1)

Where:

- x-Component of , dimensionless.

- y-Component of , dimensionless.

If we know that and , then the direction angle of the vector is:

The approximate angle of , where , is 56º.

C. 124

Step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°