Julio bought six pairs of pants for a total of $330. Dress pants cost $60 and jeans cost $50. How many of each type of pants did he buy?

3 dress pants and 3 jeans

Step-by-step explanation:

dress pants 3×60=180

jeans 3×50=150

$ 180+$150=$330

3 of each type. (3 Dress pants, 3 Jeans.)

Step-by-step explanation:

Note: you probably shouldn't use this as an actual step-by-step explanation if you need one.

Let's make this into an algebra expression:

60x + 50y = 330

x = Dress pants ($60 each)

y = Jeans ($50 each)

We aren't gonna use this expression to solve it (since it's two separate variables), but we can use it to confirm if it's correct.

Now, I'm sure there's a proper way to do this, but there's a very cheeky way to do it as well if you're just doing simple questions like this (and need to do it quickly.)

First, let's check how many types of dress pants you can buy with $330.

330/60 = 5.5.

So 5, with some pocket change. However, not enough to buy some jeans. (60*5 + 50*1 = 350 =/= 330)

So, let's remove one of the dress pants. Now you have enough:

60*4 + 50*1 = 290 =/= 330

But it doesn't equal exactly to 330. So, let's add one pair of jeans:

60*4 + 50*2 = 340 =/= 330

You can see the pattern from here. Start from the most amount you can buy with one type, add one of the other, and if they don't equal to the budget, then remove one of the first type, and add one to the other. You should get the following:

60*3 + 50*3 = 330

(Again, someone should probably send a better explanation.)

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is symmetric about the line y = 120,000.

step-by-step explanation:

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345