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Mathematics, 07.12.2020 03:50 sarahmolina246

Mai and Tyler work on the equation 25b+1=βˆ’11 together. Mai's solution is b=βˆ’25 and Tyler's is b=βˆ’28. Here is their work: Mai Tyler 25b+1=βˆ’11 25b+1=βˆ’11 25b =βˆ’10 2b+1= βˆ’55 b=βˆ’10 β‹…52 2b=βˆ’56 b=βˆ’25 b= βˆ’28 1. Do you agree with their solutions? Response area Drag and drop the correct answer in the space. 2. Explain your reasoning.

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Mai and Tyler work on the equation 25b+1=βˆ’11 together. Mai's solution is b=βˆ’25 and Tyler's is b=βˆ’28....
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