Please help me with the answer!! There is the picture of the problem^

A = 84º

B = 74º

C = 22º

Step-by-step explanation:

Since all the three angles of a triangle have to add up to be 180º, one can do...

A + B + C = 180º

So,

(4x+12) + (3x+20) + (x+4) = 180º

8x + 36 = 180º

8x = 144

x = 18

Then you just substitute x in each of the angles

A = 4(18) + 12 = 84º

B = 3(18) + 20 = 74º

C = (18) + 4 = 22º

***Math Check: 84 + 74 + 22 = 180º

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)