Use \large S_n=\frac{n}{2}\left(a_1+a_n\right) or \large S_n=\frac{n}{2}\left(2a_1+d\left(n- 1\right)\right) to find the sum of the arithmetic series when, \large a_1=35, \large a_n=105, and \large n=8

Sum =

560

Step-by-step explanation:

Given Sum = n/2{a1+an}

Govn the following

a1= 35

an = 105

n =8

Substitute into the expression

Sn = n/2(35+105)

Sn = n/2(140)

Sn = 70n

Sn = 70(8)

Sn = 560

Hence the sum of the AP is 560

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3