34 POINTS, BRAINLIEST, PLEASE HAALLPPP TT^TT PLEASE don`t respond without an answer!
A basketball is thrown upward from a height of 1.8 m at a velocity of 12 m/s. How long until it reaches the ground?
(Recall: h(t)=-4.9t^2-v_0 t+h_0, where v_0 is initial velocity and h_0 is initial height.)

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

2

step-by-step explanation:

answer: rolling a number cube and flipping a coin.

step-by-step explanation: