There are 14 teams in a basketball league. Each team plays every other team twice
during the season.
a) Suppose that you want to determine
how many games, in total, are played.
Suggest a simpler problem that you
could solve first.
b) How many games, in total, are played
during the season?

Step-by-step explanation:

Given that :

Number of teams = 14

Each team plays every other team twice ;

Using the combination formula :

nCr = n! ÷ (n-r)! r!

14C2 = 14! ÷ (14 - 2)! 2!

14C2 = 14! ÷ (12)! 2!

14C2 = (14 * 13) ÷ 2 * 1

14C2 = 182 / 2

14C2 = 91

Hence, since they are going to be playing each other twice :

2(14C2)

2 * 91 = 182games

true

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2