The probability of drawing two white cards, without replacement is 14/95, and the probability of drawing one white card is 2/5. What is the probability of drawing a second white card, given that the first card is white?

7/19

Step-by-step explanation:

Given that:

Probability of drawing 2 white cards without replacement = 14 / 95

Probability of drawing one white card = 2/5

Probability of drawing a second white card Given the first card is white will be :

P(2 white cards without replacement) = p(one white card) * p(second white card)

14 /95 = 2/5 * p

P = 14/95 ÷ 2/5

P= 14/95 * 5/2

P = 70 / 190

P = 7/ 19

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2