por que se considera que las tics se han convertido en un recurso imprescindible en el estudio de las matemáticas?

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

what am i trying to find out. you didn't put up the whole question.

step-by-step explanation:

question

why are the following expressions not monomials?

1) 3cd^x

a. the variable is in the denominato

2) x+2w

c. the expression is not a product.

3) 3/h

a. the variable is in the denominator

4) ab^-1

c. the expression is not a product.

hope this !

answer is d.

l.a. = 791.7 ft2;  

s.a. = 1,244.1 ft2

hope you got it : d