Assuming each area code is just as likely as any other, what's the probability that the area code of two back to back spam calls are 804

Complete Question:

Yanay gets a lot of spam calls. An area code is defined to be a three digit number from 200-999 inclusive. In reality, many of these area codes are not in use, but for this question we'll simplify things and assume they all are.

Assuming each area code is just as likely as any other, what's the probability that the area code of two back to back spam calls are 804?

1/6400 or 0.0000015625

Step-by-step explanation:

Given

Area Codes = 200 to 999 (inclusive)

Required

Determine the probability that back to back calls have area code 804

[First, we need to calculate the totality of area codes]

Total Area Codes = 999 - 200 + 1

Total Area Codes = 800

The probability of each code is 1/800

So, the probability of having back to back code of 804 is:

Probability = 1/800 * 1/800

Probability = (1/800)²

Probability = 1/640000

Hence, the required probability is 1/640000 or 0.0000015625

sample answer: you can determine whether each element of the domain is paired with exactly one element of the range. for example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110