2(3y+5)+y=3 what are the steps to solving this?

Step-by-step explanation: Simplifying

2(3y + -5) + -2 = 3(y + -3)

Reorder the terms:

2(-5 + 3y) + -2 = 3(y + -3)

(-5 * 2 + 3y * 2) + -2 = 3(y + -3)

(-10 + 6y) + -2 = 3(y + -3)

Reorder the terms:

-10 + -2 + 6y = 3(y + -3)

Combine like terms: -10 + -2 = -12

-12 + 6y = 3(y + -3)

Reorder the terms:

-12 + 6y = 3(-3 + y)

-12 + 6y = (-3 * 3 + y * 3)

-12 + 6y = (-9 + 3y)

Solving

-12 + 6y = -9 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.

-12 + 6y + -3y = -9 + 3y + -3y

Combine like terms: 6y + -3y = 3y

-12 + 3y = -9 + 3y + -3y

Combine like terms: 3y + -3y = 0

-12 + 3y = -9 + 0

-12 + 3y = -9

Add '12' to each side of the equation.

-12 + 12 + 3y = -9 + 12

Combine like terms: -12 + 12 = 0

0 + 3y = -9 + 12

3y = -9 + 12

Combine like terms: -9 + 12 = 3

3y = 3

Divide each side by '3'.

y = 1

Simplifying

y = 1

your answer would be 12

where is the diagram? shown below where? ?

step-by-step explanation: