the distance that a spring will stretch varies directly as the force applied to the spring. a force of 50 pounds is needed to stretch a spring 5 inches. what force is required to stretch the spring 19 inches?

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²

the answer on ed. is:

c. "the graph of f(x) has exactly two x-intercepts."

hope i could someone! : )

my answer was deleted because it was to vague the answer is 12.76 becuase its in the hundreths place. john