I = 870pie^2a^2f^2 The intensity, I of a sound wave is defined as its power output per unit area and is measured in watts per square meter (w/m^2) A sound wave's intensity can be calculated using the above equation, where a stands for the wave's amplitude in meters (m) and f stands for its frequency of vibration in hertz (Hz). If a particular sound wave has an intensity of 0.05 w/m^2 and an amplitude of 3 x 10^-5 m, which of the following is most nearly its frequency?
a. 8.77 hertz
B
80 hertz
c.6,500 hertz
d. 4 x 107 hertz

4 + 5 7/9= 9 7/9

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116