A number is 2/3 of another number. if the sum of the two numbers is 30, find the smaller number.

The numbers are 4 and 6.

Step-by-step explanation:

Let one number be represented as

x

and the other as

y

.

According to the problem:

x

=

2

3

y

and

x

+

y

=

10

From the second equation we get:

x

+

y

=

10

∴

y

=

10

−

x

(subtracting

x

from both sides)

Replacing the value of

y

in the first equation we get:

x

=

2

3

y

x

=

2

3

(

10

−

x

)

Multiplying both sides by

3

we get:

3

x

=

2

(

10

−

x

)

Opening the brackets and simplifying we get:

3

x

=

20

−

2

x

Add

2

x

to both sides.

5

x

=

20

Divide both sides by

5

.

x

=

4

Since from the second equation we have:

x

+

y

=

10

substituting

x

with

4

we get:

4

+

y

=

10

Subtract

4

from both sides.

y

=

6

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts