In a family of 11, what is the probability that there will be more boys than girls

P(all female)= 1/2 x 1/2 x 1/2 = 1/8

P(all male ) = 1/2 x 1/2 x 1/2 = 1/8

P(all one gender) = P(all female) + P(all male) = 1/8 + 1/8 = 1/4

What is the probability that a three-child family is two girls and one boy?

Each possible birth order has P=1/8. That is, P(G,G,B)=P(G,B,G)=P(B,G,G)=1/8.

So, P(2G,1B)= 3/8 and P(1G,2B)= 3/8.

This allows us to write the overall gender probability distribution for families of three children as follows:

1/8 will be three girls

3/8 will be two girls and one boy

3/8 will be one girl and two boys

1/8 will be three boys

Adding it all up, we have 1/8 + 3/8 + 3/8 + 1/8 = 1 (100%)

Step-by-step explanation:

this is a good question! i'll do some research and come back when i have the answer!