A particular type of cell doubles in number every hour. Which function can be used to find the number of cells present at the end of h hours if there are initially 4 of these cells?

The function would be

.This is in the general form

, where a is the initial value, b is the rate it increases by, and x is the amount of time.  For our function, the initial value is 4 and the rate it increases by is 2.

Step-by-step explanation:

The function would be

.This is in the general form

, where a is the initial value, b is the rate it increases by, and x is the amount of time.  For our function, the initial value is 4 and the rate it increases by is 2.

Step-by-step explanation:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.