A mini toy helicopter ascends 50 feet vertically, then flies horizontally 200 feet. Find the angle of elevation to the helicopter now as seen by an observer at the takeoff point.

10.036

Step-by-step explanation:

Remark

Draw a triangle starting with a vertical line that goes from (0,0) to (0,50).

At the point (0,50) draw a horizontal line to (200,50)

Join the point (200,50) to (0,0)

What you have is an upside down right triangle. At the point (200,50) your job is to find the angle at the vertex point.

That angle is the same as the angle of elevation.

The horizontal line is 200 feet.

The vertical line is 50 feet

Formula

Tan(angle elevation) = o/a = 50/200 = 1/4 = 0.25

Solution

tan-1(0.25) = 14.036

Conclusion

The reason you use the top angle is because you only need to do one calculation. It gives the angle of elevation because the x axis and the 200 feet are parallel. The angles are in a z formation.  so the angle you found and the angle of elevation are the 2 angles defined by the z.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.