Last year, Amy opened an investment account with $6800. At the end of the year, the amount in the account had increased by 23.5%. How much is this increase in dollars? How much money was in her account at the end of last year?

-The increase in dollars is $1598

-The amount in her account at the end of last year was $8398.

Step-by-step explanation:

To find the increase, you have to multiply the initial amount for the percentage increase:

6800*23.5%=1598

Now, to find the amount in her account at the end of last year, you have to add the initial amount plus the increase in dollars:

6800+1598=8398

According to this, the amount in her account at the end of last year was $8398.

pls refer ro the top for answer

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)