A smoke jumper jumps from a plane that is 1900 ft above the ground. The function h=-16t+1900 gives the jumper's height h in feet during the free fall at t seconds. a. How long is the jumper in free fall if the parachute opens at 1000 ft? b. How long is the jumper in free fall if the parachute opens at ft? c. What is a reasonable domain and range for the function h? a. The jumper is in free fall for nothing s if the parachute opens at 1000 ft

a) The jumper opens the parachute in 7.5 seconds.

b) The jumper opens the parachute in approximately 7.706 seconds.

c) There are two possible choices for the function:

Case a): ,

Case b): ,

Step-by-step explanation:

Note: The equation presented in statement is incorrect. The correct formula for free fall is:

(1)

Where:

- Time, measured in seconds.

- Height above the ground, measured in feet.

a) If we know that , then the final instant of the free fall stage is:

The jumper opens the parachute in 7.5 seconds.

b) How long is the jumper in free fall if the parachute opens at 950 ft?

If we know that , then the final instant of the free fall stage is:

The jumper opens the parachute in approximately 7.706 seconds.

c) There are two possible choices for the function:

Case a): ,

Case b): ,

your answer would be b

step-by-step explanation:

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

- r3ktforgood ☕