If the product of the two roots of the equation : (k - 2) x2 - 6 X + 12 = 0 is 3, then k = (a) zero
(b) 4
(c) 6
(d) 38

(c)

Step-by-step explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0

Then the product of the roots =

(k - 2)x² - 6x + 12 = 0 ← is in standard form

with a = k - 2 and c = 12 , thus

= 3 ( multiply both sides by (k - 1) )

12 = 3(k - 2) = 3k - 6 ( add 6 to both sides )

18 = 3k ( divide both sides by 3 )

6 = k → (c)

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation: