1. Given: y = -2x2 Domain
Range
Opening of the
parabola
Vertex
Axis of Symmetry
X - intercept
y - intercept

Domain: (-∞,∞) or -∞ < x < ∞ or all real numbers

Range: (-∞,0] or -∞ < y ≤ 0

Opens: Downwards since a is negative

Vertex: ( 0 , 0 )

Axis of Symmetry: x=0

x-intercept: ( 0 , 0 )

y-intercept: ( 0 , 0 )

hi there!

the answer will be d: 2

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204