A boy throws a ball into the air. The equation h=−16t^2+23t+4 models the path of the ball, where h is the height (in feet) of the ball t seconds after it is thrown. How long is the ball in the air?

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

it would open into a square depending on the type of envelope i’m not sure about the second part

3 3 6, because in every triangle the longer side is always shorter than the sum of the other two

b is the correct answer