Find the solution to the following system using substitution or elimination: y = 3x + 2
y = -2x - 8
A. (-2, -4).
B. (-3/5, -34/5).
C. (-6/5, -8/5).
D. (1, 6)

A

Explanation:

Just use substitution because it's more efficient. Plug -2x-8 into y to make -2x-8=3x+2. Add 8 to both sides to get -2x=3x+10. Subtract 3x to both sides to get -5x=10. Divide -5 to both sides to get x=-2. Now, plug in x=-2 to one of the equations, let's use y=3x+2. The equation would be y=3(-2)+2. Multiply 3 and -2 to get -6. Add -6 to 2 and you'll result with y=-4.

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

you would need to also lose 1 point for each of the other outcomes for it to be fair.

step-by-step explanation: