Y = 2x²- 5x + 2 determine the x value for the vertex and whether this value is a maximum or a minimum
a. maximum at x = -1.25
b. maximum at x = 1.25
c. minimum at x = -1.25
d. minimum at x = 1.25

D

Explanation:

Use the vertex formula, -b/2a. Because the quadratic formula is ax^2+bx+c, -b would be 5 in this case and a would be 2 in this case. Plug the numbers in and you get 5/4. The AOS or vertex would be 5/4 or 1.25. Because the a-value is a positive in this equation, the parabola would have a minimum.  

20

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3