What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1? x = –2 + sqrt(1/2) or x = –2 – sqrt(1/2)

x = 2 + sqrt(1/2) or x = 2 – sqrt(1/2)

x = –2 + sqrt(23/6) or x = –2 – sqrt(23/6)

x = 2 + sqrt(23/6) or x = 2 – sqrt(23/6)

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

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step-by-step explanation:

ok thats very interesting

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right