**PLEASE HELP** Find the equation, f(x)=a(x-h)^2+k, for a parabola that passes through the point (0,0) and has a (-3,-6) as its vertex. What is the standard form of the equation?

A.) The vertex form of the equation is f(x)= - 2/3(x+3)^2-6. The standard form of the equation is f(x)=2/3x^2+4x.

B.) The vertex form of the equation is f(x)=2/3(x+3)^2-6. The standard form of the equation is f(x)+-2/3x^2-4x.

C.) The vertex form of the equation is f(x)= - 2/3(x-3)^2-6. The standard form of the equation is f(x)=2/3x^2-4x.

D.) The vertex of the equation is f(x)=2/3(x+3)^2-6. The standard form of the equation is f(x)=2/3x^2+4x.

D) The vertex of the equation is . The standard form of the equation is .

Step-by-step explanation:

Let and (vertex).

If we know that , , and , then the standard equation results in:

And the value of is:

And the vertex form of the equation is .

Lastly, the standard form of the equation is found by algebraic means:

The standard form of the equation is .  

In consequence, the right answer is D.

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