Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (-5, -8): y = - 3x + 2

Given:

The equation of line is

To find:

The equation of line parallel to given line and passes through (-5,-8).

Solution:

Slope intercept form of a line is

where, m is slope and b is y-intercept.

On comparing the equation with the slope intercept form, we get

Slope of given line is -3.

Slope of two parallel lines are same. So, the slope of parallel line is -3.

Equation of line passes thorough the point (-5,-8) with slope -3 is

where, m is slope of the line.

Subtract 8 from both sides.

Therefore, the equation of required line is .

q: 92 degrees

hope i ^-^

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.