Find the vertex, focus, directrix, and focal width of the parabola. x = 4y2.

The vertex is (0,0), focus of the parabola is , directrix of the parabola is , focal width is .

Step-by-step explanation:

The given equation of parabola is

It can be written as

          ....(1)

The general equation of parabola is

          ... (2)

Where, (h,k) is vertex, (h+p,k) is focus, y=h-p is directrix and |4p| is focal width.

On comparing (1) and (2), we get

The vertex is (0,0).

Focus of the parabola is

Therefore focus of the parabola is .

Directrix of the parabola is

Directrix of the parabola is .

Focal width is

Focal width is .

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.