Line segment NY has endpoints N(-11, 5) and Y(3,-3). What is the equation of the perpendicular bisector of Ny?

Given:

Line segment NY has endpoints N(-11, 5) and Y(3,-3).

To find:

The equation of the perpendicular bisector of NY.

Solution:

Midpoint point of NY is

Slope of lines NY is

Product of slopes of two perpendicular lines is -1. So,

The perpendicular bisector of NY passes through (-4,1) with slope . So, the equation of perpendicular bisector of NY is

Add 1 on both sides.

Therefore, the equation of perpendicular bisector of NY is .

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-2 is the right