A rectangle has a length of x inches and a width 2 inches less than the length. If the dimensions were doubled, what would be the area, in square inches , of the new rectangle in terms of x

Option (4)

Step-by-step explanation:

Area of a rectangle = Length × width

If the dimensions of the given rectangle is doubled,

Area of the new rectangle = 2(Length) × 2(width)

                                            = 4(Length × width)

                                            = 4(x)(x - 2)

                                            = 4[x² - 2x]

                                            = 4x² - 8x

Therefore, Option (4) will be the correct option.

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

33

step-by-step explanation: g=6