Two supplementary angles are in a ratio of 7:11. find the measures of each angle

70° and 110°

Step-by-step explanation:

Supplementary angles sum to 180°

sum the parts of the ratio, 7 + 11 = 18 parts

Divide 180° by 18 to find the value of one part of the ratio.

180° ÷ 18 = 10° ← value of 1 part, thus

7 parts = 7 × 10° = 70°

11 parts = 11 × 10° = 110°

The 2 angles are 70° and 110°

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct